What is the solution for 2x^2(dy)/(dx)=piysin(pi/(2x)) ?

The solution for 2x^2(dy)/(dx)=piysin(pi/(2x)) is y=e^{cos(pi/(2x))+c_{1}}

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2x^2(dy)/(dx)=piysin(pi/(2x))

2 x^{2} \frac{d y}{d x} = π y sin (\frac{π}{2 x})

y = e^{c o s (\frac{π}{2 x}) + c_{1}}

Solution steps

2 x^{2} \frac{d y}{d x} = π y sin (\frac{π}{2 x})

Solve separable ODE:

y = e^{c o s (\frac{π}{2 x}) + c_{1}}

y = e^{c o s (\frac{π}{2 x}) + c_{1}}

y = ∣ x ∣ + ∣ x - 1 ∣, x = - 1, x = 2

\frac{d}{d x} (\frac{( x ^{3} + i x ^{2} + x + 1 )}{x ^{2} + i})

\int (1 - y) d y

\frac{d y}{d t} + 0.3 t y = 5 t, y (0) = 6

x \to 3 + lim (\frac{8}{x - 3})

What is the solution for 2x^2(dy)/(dx)=piysin(pi/(2x)) ?
The solution for 2x^2(dy)/(dx)=piysin(pi/(2x)) is y=e^{cos(pi/(2x))+c_{1}}