What is the derivative of 2sin(x-cos(x)) ?

The derivative of 2sin(x-cos(x)) is 2cos(x)+sin(x)

What is the first derivative of 2sin(x-cos(x)) ?

The first derivative of 2sin(x-cos(x)) is 2cos(x)+sin(x)

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\frac{d}{d x} (2 sin (x) - cos (x))

2 cos (x) + sin (x)

Solution steps

\frac{d}{d x} (2 sin (x) - cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 sin (x)) - \frac{d}{d x} (cos (x))

\frac{d}{d x} (2 sin (x)) = 2 cos (x)

\frac{d}{d x} (cos (x)) = - sin (x)

= 2 cos (x) - (- sin (x))

Simplify

= 2 cos (x) + sin (x)

(e^{- 3 y}) y^{^{'}} = e^{8 x}, y (0) = 12

\frac{\partial}{\partial x} (yz e^{x z} - 2)

\int_{0}^{\infty} x e^{- \frac{x}{y}} d x

y^{^{''}} - 6 y^{^{'}} + 7 y = 0

\frac{\partial}{\partial x} (arctan (x) y)

What is the derivative of 2sin(x-cos(x)) ?
The derivative of 2sin(x-cos(x)) is 2cos(x)+sin(x)
What is the first derivative of 2sin(x-cos(x)) ?
The first derivative of 2sin(x-cos(x)) is 2cos(x)+sin(x)