What is the f(x)=ln(x+sqrt(x^2+1)) ?

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f(x)=ln(x+sqrt(x^2+1))

f (x) = ln (x + x^{2} + 1)

Domain : - \infty < x < \infty

Range : - \infty < f (x) < \infty

X Intercepts : (0, 0), Y Intercepts : (0, 0)

Asymptotes : None

Extreme Points : None

Interval Notation

Domain : (- \infty, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

ln (x + x^{2} + 1) : - \infty < x < \infty

Range of

ln (x + x^{2} + 1) : - \infty < f (x) < \infty

Axis interception points of

ln (x + x^{2} + 1) :

X Intercepts

: (0, 0),

Y Intercepts

: (0, 0)

Asymptotes of

ln (x + x^{2} + 1) :

None

Extreme Points of

ln (x + x^{2} + 1) :

None

\int 49 - t^{2} d t

\frac{\partial}{\partial x} (e^{- 4 x} cos (5 x))

\frac{\partial}{\partial x} (\frac{( x - 3 y )}{x + 3 y})

\frac{d}{d x} (t e^{2 x})

\frac{d ^{2}}{d x ^{2}} (\frac{1}{x})