What is the tangent of 2sqrt(x)(1.2) ?

The tangent of 2sqrt(x)(1.2) is y=(1.2}{sqrt(a_{0)}}x+\frac{6sqrt(a_{0)})/5

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tangent of 2sqrt(x)(1.2)

tangent of

2 x (1.2)

y = \frac{1.2}{a _{0}} x + \frac{6 a _{0}}{5}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 2.4 a_{0})

Find the slope of

y = 2 x 1.2 : \frac{d y}{d x} = \frac{1.2}{x}

Compute the slope of

y = 2 x 1.2

x = a_{0} : m = \frac{1.2}{a _{0}}

Find the line with slope m=

\frac{1.2}{a _{0}}

and passing through

(a_{0}, 2.4 a_{0}) : y = \frac{1.2}{a _{0}} x + \frac{6 a _{0}}{5}

y = \frac{1.2}{a _{0}} x + \frac{6 a _{0}}{5}

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x \to 0 + lim (x^{x^{2}})

\int_{0}^{\infty} \frac{x}{x ^{2} + 1} d x

\int e^{15 x} (15) d x

What is the tangent of 2sqrt(x)(1.2) ?
The tangent of 2sqrt(x)(1.2) is y=(1.2}{sqrt(a_{0)}}x+\frac{6sqrt(a_{0)})/5