What is the integral from 0 to infinity of x/(x^2+1) ?

The integral from 0 to infinity of x/(x^2+1) is diverges

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integral from 0 to infinity of x/(x^2+1)

\int_{0}^{\infty} \frac{x}{x ^{2} + 1} d x

diverges

Solution steps

\int_{0}^{\infty} \frac{x}{x ^{2} + 1} d x

Compute the indefinite integral:

\int \frac{x}{x ^{2} + 1} d x = \frac{1}{2} ln x^{2} + 1 + C

Compute the boundaries:

\int_{0}^{\infty} \frac{x}{x ^{2} + 1} d x =

diverges

= diverges

\int e^{15 x} (15) d x

x \to 4 lim (\frac{x - 4}{x - 2})

f (x) = cos (x), g (x) = - cos (x) + 2

(- 1.4) (3.12)

y = (- x^{2} + 10 x - 21)^{3}

What is the integral from 0 to infinity of x/(x^2+1) ?
The integral from 0 to infinity of x/(x^2+1) is diverges