What is the limit as n approaches infinity of 4^n ?

The limit as n approaches infinity of 4^n is infinity

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limit as n approaches infinity of 4^n

n \to \infty lim (4^{n})

\infty

Solution steps

n \to \infty lim (4^{n})

Apply the common limit:

x \to \infty lim (a^{x}) = \infty, a > 1

= \infty

x = - 2, x = 3, y = 2 x^{2} + 10, y = 0

f (x) = 9 e^{x} cos (x), at x = 0

\frac{\partial}{\partial v} (4 u cos (v))

\frac{\partial}{\partial x} (\frac{1}{1 + e ^{- x}})

\int \frac{sin ( 3 x )}{3} d x

What is the limit as n approaches infinity of 4^n ?
The limit as n approaches infinity of 4^n is infinity