What is the tangent of y=(-4x)/(x^2+1),(-1,2) ?

The tangent of y=(-4x)/(x^2+1),(-1,2) is y=2

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tangent of y=(-4x)/(x^2+1),(-1,2)

tangent of

y = \frac{- 4 x}{x ^{2} + 1}, (- 1, 2)

y = 2

Solution steps

Find the slope of

y = \frac{- 4 x}{x ^{2} + 1} : \frac{d y}{d x} = - \frac{4 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}}

Compute the slope of

y = \frac{- 4 x}{x ^{2} + 1}

(- 1, 2) : m = 0

Find the line with slope m=

0

and passing through

(- 1, 2) : y = 2

y = 2

θ \to 0 lim (\frac{sin ( 5 θ )}{θ + tan ( 7 θ )})

\int (z + 1) 3 z + 2 d z

\int 10 x sec (x) tan (x) d x

\frac{\partial}{\partial x} (ln (2 x + 3 y + 6 z))

\int x^{- 0.1} d x

What is the tangent of y=(-4x)/(x^2+1),(-1,2) ?
The tangent of y=(-4x)/(x^2+1),(-1,2) is y=2