What is the derivative of \sqrt[3]{x^2}+2sqrt(x^3) ?

The derivative of \sqrt[3]{x^2}+2sqrt(x^3) is 2/(3x^{1/3)}+3sqrt(x)

What is the first derivative of \sqrt[3]{x^2}+2sqrt(x^3) ?

The first derivative of \sqrt[3]{x^2}+2sqrt(x^3) is 2/(3x^{1/3)}+3sqrt(x)

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\frac{2}{3 x ^{\frac{1}{3}}} + 3 x

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (2 x^{3}) = 3 x

= \frac{2}{3 x ^{\frac{1}{3}}} + 3 x

\frac{\partial}{\partial x} (5 e^{yz} cos (x yz))

x^{2} - 8 x + 15, 0

\frac{d}{d x} (2 x e^{- \frac{x ^{2}}{2}})

\frac{\partial}{\partial y} (y x)

f (x) = 6 x^{2} - 4 x + 4, (1, 6)

What is the derivative of \sqrt[3]{x^2}+2sqrt(x^3) ?
The derivative of \sqrt[3]{x^2}+2sqrt(x^3) is 2/(3x^{1/3)}+3sqrt(x)
What is the first derivative of \sqrt[3]{x^2}+2sqrt(x^3) ?
The first derivative of \sqrt[3]{x^2}+2sqrt(x^3) is 2/(3x^{1/3)}+3sqrt(x)