What is the derivative of f(x)=3x^4-5x^3-x^2+4x+9 ?

The derivative of f(x)=3x^4-5x^3-x^2+4x+9 is 12x^3-15x^2-2x+4

What is the first derivative of f(x)=3x^4-5x^3-x^2+4x+9 ?

The first derivative of f(x)=3x^4-5x^3-x^2+4x+9 is 12x^3-15x^2-2x+4

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derivative of

f (x) = 3 x^{4} - 5 x^{3} - x^{2} + 4 x + 9

12 x^{3} - 15 x^{2} - 2 x + 4

Solution steps

\frac{d}{d x} (3 x^{4} - 5 x^{3} - x^{2} + 4 x + 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{4}) - \frac{d}{d x} (5 x^{3}) - \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4 x) + \frac{d}{d x} (9)

\frac{d}{d x} (3 x^{4}) = 12 x^{3}

\frac{d}{d x} (5 x^{3}) = 15 x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (9) = 0

= 12 x^{3} - 15 x^{2} - 2 x + 4 + 0

Simplify

= 12 x^{3} - 15 x^{2} - 2 x + 4

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What is the derivative of f(x)=3x^4-5x^3-x^2+4x+9 ?
The derivative of f(x)=3x^4-5x^3-x^2+4x+9 is 12x^3-15x^2-2x+4
What is the first derivative of f(x)=3x^4-5x^3-x^2+4x+9 ?
The first derivative of f(x)=3x^4-5x^3-x^2+4x+9 is 12x^3-15x^2-2x+4