What is the integral of 1/(sqrt(2)) ?

The integral of 1/(sqrt(2)) is 1/(sqrt(2))x+C

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integral of 1/(sqrt(2))

\int \frac{1}{2} d x

\frac{1}{2} x + C

Solution steps

\int \frac{1}{2} d x

Integral of a constant:

\int a d x = a x

= \frac{1}{2} x

Add a constant to the solution

= \frac{1}{2} x + C

\int_{1}^{2} \frac{1}{x - 1} d x

\int \frac{16}{x ^{2} - 1} d x

x \frac{d y}{d x} - (1 + x) y = x y^{2}

\int \frac{3 x ^{2} + 1}{x ^{2} 4 - x ^{2}} d x

\frac{d}{d x} (\frac{cos ( x )}{x ^{4}})

What is the integral of 1/(sqrt(2)) ?
The integral of 1/(sqrt(2)) is 1/(sqrt(2))x+C