What is the d/(dθ)(1-2sin(θ)) ?

The d/(dθ)(1-2sin(θ)) is -2cos(θ)

What is the first d/(dθ)(1-2sin(θ)) ?

The first d/(dθ)(1-2sin(θ)) is -2cos(θ)

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\frac{d}{d θ} (1 - 2 sin (θ))

- 2 cos (θ)

Solution steps

\frac{d}{d θ} (1 - 2 sin (θ))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (1) - \frac{d}{d θ} (2 sin (θ))

\frac{d}{d θ} (1) = 0

\frac{d}{d θ} (2 sin (θ)) = 2 cos (θ)

= 0 - 2 cos (θ)

Simplify

= - 2 cos (θ)

x 7^{x}

f (x) = 18 x^{3} - x

\frac{\partial}{\partial x} (5 tan (5 x))

\frac{d}{d x} (\frac{cos ( 2 x )}{sin ( 2 x )})

(x - 1) d y + (y - x^{- 2} + 2 x^{- 3}) d x = 0