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Popular >

integral from-1 to 0 of x^3+1

Solution

\int_{- 1}^{0} x^{3} + 1 d x

Solution

\frac{3}{4}

+1

Decimal Notation

0.75

Solution steps

\int_{- 1}^{0} x^{3} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{0} x^{3} d x + \int_{- 1}^{0} 1 d x

\int_{- 1}^{0} x^{3} d x = - \frac{1}{4}

\int_{- 1}^{0} 1 d x = 1

= - \frac{1}{4} + 1

Simplify

- \frac{1}{4} + 1 : \frac{3}{4}

= \frac{3}{4}

Popular Examples

derivative of 18sqrt(x)-3x derivative of

18 x - 3 x

tangent of f(x)=-1-9x^2,\at x=3 tangent of

f (x) = - 1 - 9 x^{2}, at x = 3

derivative of sqrt(r^2-x^2)derivative of

r^{2} - x^{2}

area x^2,4 area

x^{2}, 4

integral of 1/(xsqrt(x+6))

\int \frac{1}{x x + 6} d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 0 of x^3+1 ?
The integral from-1 to 0 of x^3+1 is 3/4