What is the tangent of f(x)=sqrt(7x+2),(2,4) ?

The tangent of f(x)=sqrt(7x+2),(2,4) is y= 7/8 x+9/4

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tangent of f(x)=sqrt(7x+2),(2,4)

tangent of

f (x) = 7 x + 2, (2, 4)

y = \frac{7}{8} x + \frac{9}{4}

Solution steps

Find the slope of

f (x) = 7 x + 2 : \frac{df ( x )}{d x} = \frac{7}{2 7 x + 2}

Compute the slope of

f (x) = 7 x + 2

(2, 4) : m = \frac{7}{8}

Find the line with slope m=

\frac{7}{8}

and passing through

(2, 4) : y = \frac{7}{8} x + \frac{9}{4}

y = \frac{7}{8} x + \frac{9}{4}

x y^{^{'}} + y = e^{x}, y (1) = 1

(3, 6), (5, - 8)

\frac{\partial}{\partial x} (ln (x + t^{2}))

x^{2} - 10 x + 4

\frac{\partial}{\partial y} (\frac{1}{x + 2 y})

What is the tangent of f(x)=sqrt(7x+2),(2,4) ?
The tangent of f(x)=sqrt(7x+2),(2,4) is y= 7/8 x+9/4