What is the tangent of-52x^2+2x+2 ?

The tangent of-52x^2+2x+2 is y=(-104a_{0}+2)x+52a_{0}^2+2

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tangent of-52x^2+2x+2

tangent of

- 52 x^{2} + 2 x + 2

y = (- 104 a_{0} + 2) x + 52 a_{0}^{2} + 2

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, - 52 a_{0}^{2} + 2 a_{0} + 2)

Find the slope of

y = - 52 x^{2} + 2 x + 2 : \frac{d y}{d x} = - 104 x + 2

Compute the slope of

y = - 52 x^{2} + 2 x + 2

x = a_{0} : m = - 104 a_{0} + 2

Find the line with slope m=

- 104 a_{0} + 2

and passing through

(a_{0}, - 52 a_{0}^{2} + 2 a_{0} + 2) : y = (- 104 a_{0} + 2) x + 52 a_{0}^{2} + 2

y = (- 104 a_{0} + 2) x + 52 a_{0}^{2} + 2

y^{^{''}} + 4 y^{^{'}} = - 6 x - 3

\frac{\partial}{\partial x} (- sin (x) cos (y))

\int_{0}^{7} 2 e^{x} d x

n = 2 \sum \infty \frac{1}{( n ^{3} - n )}

\frac{0.32}{( 15.5 \cdot s + 1 ) \cdot s}

What is the tangent of-52x^2+2x+2 ?
The tangent of-52x^2+2x+2 is y=(-104a_{0}+2)x+52a_{0}^2+2