What is (\partial)/(\partial x)(-sin(x)cos(y)) ?

The answer to (\partial)/(\partial x)(-sin(x)cos(y)) is -cos(y)cos(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(\partial)/(\partial x)(-sin(x)cos(y))

\frac{\partial}{\partial x} (- sin (x) cos (y))

- cos (y) cos (x)

Solution steps

\frac{\partial}{\partial x} (- sin (x) cos (y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - cos (y) \frac{\partial}{\partial x} (sin (x))

Apply the common derivative:

\frac{\partial}{\partial x} (sin (x)) = cos (x)

= - cos (y) cos (x)

n = 2 \sum \infty \frac{1}{( n ^{3} - n )}

\frac{d y}{d x} = \frac{1}{3} y (8 - y), y (0) = 1

2 x^{4} y^{^{'}} = k

\int (2 x^{3} + 6 x)^{2} d x

\frac{\partial}{\partial x} (5 ln (x y))

What is (\partial)/(\partial x)(-sin(x)cos(y)) ?
The answer to (\partial)/(\partial x)(-sin(x)cos(y)) is -cos(y)cos(x)