What is the integral of (2x^3+6x)^2 ?

The integral of (2x^3+6x)^2 is (4x^7)/7+(24x^5)/5+12x^3+C

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integral of (2x^3+6x)^2

\int (2 x^{3} + 6 x)^{2} d x

\frac{4 x ^{7}}{7} + \frac{24 x ^{5}}{5} + 12 x^{3} + C

Solution steps

\int (2 x^{3} + 6 x)^{2} d x

Expand

(2 x^{3} + 6 x)^{2} : 4 x^{6} + 24 x^{4} + 36 x^{2}

= \int 4 x^{6} + 24 x^{4} + 36 x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 x^{6} d x + \int 24 x^{4} d x + \int 36 x^{2} d x

\int 4 x^{6} d x = \frac{4 x ^{7}}{7}

\int 24 x^{4} d x = \frac{24 x ^{5}}{5}

\int 36 x^{2} d x = 12 x^{3}

= \frac{4 x ^{7}}{7} + \frac{24 x ^{5}}{5} + 12 x^{3}

Add a constant to the solution

= \frac{4 x ^{7}}{7} + \frac{24 x ^{5}}{5} + 12 x^{3} + C

\frac{\partial}{\partial x} (5 ln (x y))

x^{^{''}} + 20 x^{^{'}} + 500 x = 12

y = x^{2} (1 - 2 x)

\int_{0}^{4} x - x + 2 d x

x \to 1 lim (\frac{- 2}{x - 1})

What is the integral of (2x^3+6x)^2 ?
The integral of (2x^3+6x)^2 is (4x^7)/7+(24x^5)/5+12x^3+C