What is the derivative of y= x/(4x+7) ?

The derivative of y= x/(4x+7) is 7/((4x+7)^2)

What is the first derivative of y= x/(4x+7) ?

The first derivative of y= x/(4x+7) is 7/((4x+7)^2)

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derivative of

y = \frac{x}{4 x + 7}

\frac{7}{( 4 x + 7 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x}{4 x + 7})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d x}{d x} ( 4 x + 7 ) - \frac{d}{d x} ( 4 x + 7 ) x}{( 4 x + 7 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (4 x + 7) = 4

= \frac{1 \cdot ( 4 x + 7 ) - 4 x}{( 4 x + 7 ) ^{2}}

Simplify

= \frac{7}{( 4 x + 7 ) ^{2}}

f (x) = ln (cos (x))

\frac{d}{d x} (9 e^{x})

x \to 0 lim (\frac{2 ^{x} - 5 ^{x}}{x})

\frac{d}{d x} (2 x^{3} - 3 x^{2})

\int (\frac{9}{x} + \frac{x}{9}) d x

What is the derivative of y= x/(4x+7) ?
The derivative of y= x/(4x+7) is 7/((4x+7)^2)
What is the first derivative of y= x/(4x+7) ?
The first derivative of y= x/(4x+7) is 7/((4x+7)^2)