What is the derivative of 2x^3-3x^2 ?

The derivative of 2x^3-3x^2 is 6x^2-6x

What is the first derivative of 2x^3-3x^2 ?

The first derivative of 2x^3-3x^2 is 6x^2-6x

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\frac{d}{d x} (2 x^{3} - 3 x^{2})

6 x^{2} - 6 x

Solution steps

\frac{d}{d x} (2 x^{3} - 3 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (3 x^{2})

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

= 6 x^{2} - 6 x

\int (\frac{9}{x} + \frac{x}{9}) d x

y = - 2 x + 2

\int (- 20 x^{3} - 6 x^{- 3}) d x

\frac{\partial}{\partial x} (\frac{7 y - 7 x}{y ^{2} + 2 x ^{2}})

(x^{2} - 2 x - 2 sin (x - 2))^{^{'}}

What is the derivative of 2x^3-3x^2 ?
The derivative of 2x^3-3x^2 is 6x^2-6x
What is the first derivative of 2x^3-3x^2 ?
The first derivative of 2x^3-3x^2 is 6x^2-6x