What is the limit as x approaches 2 of (x^2-9)/(x-3) ?

The limit as x approaches 2 of (x^2-9)/(x-3) is 5

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limit as x approaches 2 of (x^2-9)/(x-3)

x \to 2 lim (\frac{x ^{2} - 9}{x - 3})

5

Solution steps

x \to 2 lim (\frac{x ^{2} - 9}{x - 3})

Plug in the value

x = 2

= \frac{2 ^{2} - 9}{2 - 3}

Simplify

\frac{2 ^{2} - 9}{2 - 3} : 5

= 5

p (θ) = 3 θ

x y^{^{'}} = \frac{y ^{2}}{x} + y

y^{^{'}} = 1 + (\frac{y}{x})

f (x) = 1 + x^{256} - 1

\frac{d}{d x} (2 x 36 - x^{2})

What is the limit as x approaches 2 of (x^2-9)/(x-3) ?
The limit as x approaches 2 of (x^2-9)/(x-3) is 5