What is the derivative of y=(3x^3+7)^2 ?

The derivative of y=(3x^3+7)^2 is 18x^2(3x^3+7)

What is the first derivative of y=(3x^3+7)^2 ?

The first derivative of y=(3x^3+7)^2 is 18x^2(3x^3+7)

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derivative of

y = (3 x^{3} + 7)^{2}

18 x^{2} (3 x^{3} + 7)

Solution steps

\frac{d}{d x} ((3 x^{3} + 7)^{2})

Apply the chain rule:

2 (3 x^{3} + 7) \frac{d}{d x} (3 x^{3} + 7)

= 2 (3 x^{3} + 7) \frac{d}{d x} (3 x^{3} + 7)

\frac{d}{d x} (3 x^{3} + 7) = 9 x^{2}

= 2 (3 x^{3} + 7) \cdot 9 x^{2}

Simplify

= 18 x^{2} (3 x^{3} + 7)

\int (x + 2)^{- 1} d x

\frac{d y}{d x} = 7 x^{2} \cdot \frac{1}{5 y ^{2}}

\frac{d}{d x} (7 x^{\frac{1}{3}})

x \to 2 lim (\frac{2}{x - 2})

- \frac{1}{( 1 + x ) ^{2}}

What is the derivative of y=(3x^3+7)^2 ?
The derivative of y=(3x^3+7)^2 is 18x^2(3x^3+7)
What is the first derivative of y=(3x^3+7)^2 ?
The first derivative of y=(3x^3+7)^2 is 18x^2(3x^3+7)