What is the integral of (x+2)^{-1} ?

The integral of (x+2)^{-1} is ln|x+2|+C

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integral of (x+2)^{-1}

\int (x + 2)^{- 1} d x

ln ∣ x + 2 ∣ + C

Solution steps

\int (x + 2)^{- 1} d x

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= \int \frac{1}{x + 2} d x

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = x + 2

= ln ∣ x + 2 ∣

Add a constant to the solution

= ln ∣ x + 2 ∣ + C

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- \frac{1}{( 1 + x ) ^{2}}

\frac{d}{d x} (3 x^{2} - x + 12)