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Popular >

x^'=2x

Solution

x^{^{'}} = 2 x

Solution

x = e^{2 t + c_{1}}

Solution steps

x^{'} (t) = 2 x

Solve separable ODE:

x = e^{2 t + c_{1}}

x = e^{2 t + c_{1}}

Popular Examples

(dy)/(dt)-y=2cos(kt),y(0)=7

\frac{d y}{d t} - y = 2 cos (k t), y (0) = 7

(dy)/(dt)=((4t+y))/(4y-t)

\frac{d y}{d t} = \frac{( 4 t + y )}{4 y - t}

(dy)/(dx)=1+x^2+y^2+x^2y^2

\frac{d y}{d x} = 1 + x^{2} + y^{2} + x^{2} y^{2}

derivative of sqrt(x-2\sqrt{x-2)}

\frac{d}{d x} (x - 2 x - 2)

derivative of (1+x^{1/2})

\frac{d}{d x} ((1 + x)^{\frac{1}{2}})

Frequently Asked Questions (FAQ)

What is the solution for x^'=2x ?
The solution for x^'=2x is x=e^{2t+c_{1}}