What is the solution for (dy)/(dx)=1+x^2+y^2+x^2y^2 ?

The solution for (dy)/(dx)=1+x^2+y^2+x^2y^2 is y=tan((x^3)/3+x+c_{1})

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(dy)/(dx)=1+x^2+y^2+x^2y^2

\frac{d y}{d x} = 1 + x^{2} + y^{2} + x^{2} y^{2}

y = tan (\frac{x ^{3}}{3} + x + c_{1})

Solution steps

\frac{d y}{d x} = 1 + x^{2} + y^{2} + x^{2} y^{2}

Solve separable ODE:

y = tan (\frac{x ^{3}}{3} + x + c_{1})

y = tan (\frac{x ^{3}}{3} + x + c_{1})

\frac{d}{d x} (x - 2 x - 2)

\frac{d}{d x} ((1 + x)^{\frac{1}{2}})

\int (cos (x))^{2} \cdot sin (x) d x

\frac{d}{d x} (x^{2} - x - ln (x))

\int_{- 1}^{2} (8 - x^{2}) d x

What is the solution for (dy)/(dx)=1+x^2+y^2+x^2y^2 ?
The solution for (dy)/(dx)=1+x^2+y^2+x^2y^2 is y=tan((x^3)/3+x+c_{1})