What is the d/(dt)(7sin^3(t)) ?

The d/(dt)(7sin^3(t)) is 21sin^2(t)cos(t)

What is the first d/(dt)(7sin^3(t)) ?

The first d/(dt)(7sin^3(t)) is 21sin^2(t)cos(t)

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\frac{d}{d t} (7 sin^{3} (t))

21 sin^{2} (t) cos (t)

Solution steps

\frac{d}{d t} (7 sin^{3} (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d t} (sin^{3} (t))

Apply the chain rule:

3 (sin (t))^{2} \frac{d}{d t} (sin (t))

= 3 (sin (t))^{2} \frac{d}{d t} (sin (t))

\frac{d}{d t} (sin (t)) = cos (t)

= 7 \cdot 3 (sin (t))^{2} cos (t)

Simplify

= 21 sin^{2} (t) cos (t)

\int_{4}^{7} (x - 5)^{2} d x

y^{^{'}} + y = e^{x}, y (0) = 6

y = 6 cos (3 x), y = 6 sin (3 x), (0, \frac{π}{8})

\frac{\partial}{\partial x} (\frac{x}{x ^{5} - y ^{5}})

x \to 2 lim (\frac{∣ 2 - x ∣}{2 - x})

What is the d/(dt)(7sin^3(t)) ?
The d/(dt)(7sin^3(t)) is 21sin^2(t)cos(t)
What is the first d/(dt)(7sin^3(t)) ?
The first d/(dt)(7sin^3(t)) is 21sin^2(t)cos(t)