What is the derivative of acos(t+bsin(t)) ?

The derivative of acos(t+bsin(t)) is 0

What is the first derivative of acos(t+bsin(t)) ?

The first derivative of acos(t+bsin(t)) is 0

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\frac{d}{d x} (a cos (t) + b sin (t))

0

Solution steps

\frac{d}{d x} (a cos (t) + b sin (t))

Treat

a, b, t

as a constant

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

y = 6 x, y = \frac{2}{3} x, y = 40 - x^{2}

\int x (2 x^{2} + 1)^{\frac{3}{2}} d x

\frac{\partial}{\partial x} (x^{2} \cdot cos (x y))

y = 10 x^{2}, y^{2} = \frac{1}{10} x

x \to 3 - lim (\frac{1}{( x - 3 ) ^{2}})

What is the derivative of acos(t+bsin(t)) ?
The derivative of acos(t+bsin(t)) is 0
What is the first derivative of acos(t+bsin(t)) ?
The first derivative of acos(t+bsin(t)) is 0