What is the derivative of 7e^x+8/(\sqrt[3]{x}) ?

The derivative of 7e^x+8/(\sqrt[3]{x}) is 7e^x-8/(3x^{4/3)}

What is the first derivative of 7e^x+8/(\sqrt[3]{x}) ?

The first derivative of 7e^x+8/(\sqrt[3]{x}) is 7e^x-8/(3x^{4/3)}

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Popular >

7 e^{x} - \frac{8}{3 x ^{\frac{4}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (7 e^{x}) = 7 e^{x}

= 7 e^{x} - \frac{8}{3 x ^{\frac{4}{3}}}

\frac{d}{d x} ((1 + \frac{3}{x})^{x})

\frac{\partial}{\partial x} (\frac{( 2 x - 5 y )}{2 x + 5 y})

\int_{0}^{π} 6 sin^{4} (x) d x

y = r^{2} - x^{2}, y = 0

\frac{\partial}{\partial x} ((ln (x))^{2})

What is the derivative of 7e^x+8/(\sqrt[3]{x}) ?
The derivative of 7e^x+8/(\sqrt[3]{x}) is 7e^x-8/(3x^{4/3)}
What is the first derivative of 7e^x+8/(\sqrt[3]{x}) ?
The first derivative of 7e^x+8/(\sqrt[3]{x}) is 7e^x-8/(3x^{4/3)}