What is y=sqrt(r^2-x^2),y=0 ?

The solution to y=sqrt(r^2-x^2),y=0 is

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y=sqrt(r^2-x^2),y=0

y = r^{2} - x^{2}, y = 0

(r \in R, r \in R, x = r, x = - r, y = 0 y = 0)

Solution steps

[y = r^{2} - x^{2} y = 0]

Solve

y = r^{2} - x^{2}

for

y = 0 : (r \in R, x = r, y = 0), (r \in R, x = - r, y = 0)

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

y = r^{2} - x^{2}, y = 0

are

(r \in R, r \in R, x = r, x = - r, y = 0 y = 0)

\frac{\partial}{\partial x} ((ln (x))^{2})

x, at x = 144

\int \frac{x ^{3} + x ^{2} - x ^{5}}{x ^{6}} d x

\frac{d}{d x} (\frac{1}{4} (x^{4} + 8))

g (x) = 3 x^{4} - 140 x^{3}