What is the tangent of f(x)=sqrt(x^3+3),(1,2) ?

The tangent of f(x)=sqrt(x^3+3),(1,2) is y= 3/4 x+5/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=sqrt(x^3+3),(1,2)

tangent of

f (x) = x^{3} + 3, (1, 2)

y = \frac{3}{4} x + \frac{5}{4}

Solution steps

Find the slope of

f (x) = x^{3} + 3 : \frac{df ( x )}{d x} = \frac{3 x ^{2}}{2 x ^{3} + 3}

Compute the slope of

f (x) = x^{3} + 3

(1, 2) : m = \frac{3}{4}

Find the line with slope m=

\frac{3}{4}

and passing through

(1, 2) : y = \frac{3}{4} x + \frac{5}{4}

y = \frac{3}{4} x + \frac{5}{4}

\int - 3 x d x

e^{3 t}

\int \frac{1}{x ^{2} + 4 x} d x

y^{^{''}} - y^{^{'}} - 2 y = - 6 t + 6 t^{2}

\int \frac{1}{2 x ^{3} + x} d x

What is the tangent of f(x)=sqrt(x^3+3),(1,2) ?
The tangent of f(x)=sqrt(x^3+3),(1,2) is y= 3/4 x+5/4