What is (\partial)/(\partial x)(5sin(xy)) ?

The answer to (\partial)/(\partial x)(5sin(xy)) is 5cos(xy)y

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(\partial)/(\partial x)(5sin(xy))

\frac{\partial}{\partial x} (5 sin (x y))

5 cos (x y) y

Solution steps

\frac{\partial}{\partial x} (5 sin (x y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{\partial}{\partial x} (sin (x y))

Apply the chain rule:

cos (x y) \frac{\partial}{\partial x} (x y)

= cos (x y) \frac{\partial}{\partial x} (x y)

\frac{\partial}{\partial x} (x y) = y

= 5 cos (x y) y

\frac{d}{d x} (\frac{x ^{2}}{3 + x})

y^{^{'}} + 6 x y^{2} = 0

\frac{d}{d x} (\frac{1000}{x})

\frac{d ^{2}}{d x ^{2}} (arctan (x))

\frac{d}{d x} (sin^{l n (x)} (9 x))

What is (\partial)/(\partial x)(5sin(xy)) ?
The answer to (\partial)/(\partial x)(5sin(xy)) is 5cos(xy)y