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Popular >

y^'+6xy^2=0

Solution

y^{^{'}} + 6 x y^{2} = 0

Solution

y = - \frac{1}{- 3 x ^{2} + c _{1}}

Solution steps

y^{'} (x) + 6 x y^{2} = 0

Solve separable ODE:

y = - \frac{1}{- 3 x ^{2} + c _{1}}

y = - \frac{1}{- 3 x ^{2} + c _{1}}

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Frequently Asked Questions (FAQ)

What is the solution for y^'+6xy^2=0 ?
The solution for y^'+6xy^2=0 is y=-1/(-3x^2+c_{1)}