What is the integral of 4/(\sqrt[4]{x^3)} ?

The integral of 4/(\sqrt[4]{x^3)} is 16\sqrt[4]{x}+C

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integral of 4/(\sqrt[4]{x^3)}

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

assuming

x \geq 0

= 4 \cdot \int \frac{1}{x ^{\frac{3}{4}}} d x

Apply the Power Rule

: 4 x^{\frac{1}{4}}

= 4 \cdot 4 x^{\frac{1}{4}}

Simplify

Add a constant to the solution

arccsc (- 4 t^{2})

\frac{\partial}{\partial x} (5 x (3 + y)^{- 1})

\frac{d ^{2}}{d x ^{2}} (7 cos (3 x))

\frac{d}{d x} (1 - 2 x - 3 x^{2})

\int \frac{1}{x ^{2} ( 9 + x ^{2} )} d x

What is the integral of 4/(\sqrt[4]{x^3)} ?
The integral of 4/(\sqrt[4]{x^3)} is 16\sqrt[4]{x}+C