What is the derivative of f(x)=x-9 ?

The derivative of f(x)=x-9 is 1

What is the first derivative of f(x)=x-9 ?

The first derivative of f(x)=x-9 is 1

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derivative of

f (x) = x - 9

1

Solution steps

\frac{d}{d x} (x - 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (9)

\frac{d x}{d x} = 1

\frac{d}{d x} (9) = 0

= 1 - 0

Simplify

= 1

\int \frac{1}{- x ^{2} - 6 x + 40} d x

x \to 0 lim (cot^{2} (x))

x \to 2 lim (\frac{1}{x - 2})

\int \frac{x ^{2} + 4 x + 1}{x ^{3} + x} d x

\frac{d}{d x} (\frac{( x ^{2} - 1 )}{x ^{2}})

What is the derivative of f(x)=x-9 ?
The derivative of f(x)=x-9 is 1
What is the first derivative of f(x)=x-9 ?
The first derivative of f(x)=x-9 is 1