What is the integral of sqrt(x)(x^3-2x^2) ?

The integral of sqrt(x)(x^3-2x^2) is 2/9 x^{9/2}-4/7 x^{7/2}+C

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integral of sqrt(x)(x^3-2x^2)

\int x (x^{3} - 2 x^{2}) d x

\frac{2}{9} x^{\frac{9}{2}} - \frac{4}{7} x^{\frac{7}{2}} + C

Solution steps

\int x (x^{3} - 2 x^{2}) d x

Expand

x (x^{3} - 2 x^{2}) : x^{\frac{7}{2}} - 2 x^{\frac{5}{2}}

= \int x^{\frac{7}{2}} - 2 x^{\frac{5}{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{\frac{7}{2}} d x - \int 2 x^{\frac{5}{2}} d x

\int x^{\frac{7}{2}} d x = \frac{2}{9} x^{\frac{9}{2}}

\int 2 x^{\frac{5}{2}} d x = \frac{4}{7} x^{\frac{7}{2}}

= \frac{2}{9} x^{\frac{9}{2}} - \frac{4}{7} x^{\frac{7}{2}}

Add a constant to the solution

= \frac{2}{9} x^{\frac{9}{2}} - \frac{4}{7} x^{\frac{7}{2}} + C

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What is the integral of sqrt(x)(x^3-2x^2) ?
The integral of sqrt(x)(x^3-2x^2) is 2/9 x^{9/2}-4/7 x^{7/2}+C