What is the derivative of x^2+xy ?

The derivative of x^2+xy is 2x+y+x(dy)/(dx)

What is the first derivative of x^2+xy ?

The first derivative of x^2+xy is 2x+y+x(dy)/(dx)

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\frac{d}{d x} (x^{2} + x y)

2 x + y + x \frac{d y}{d x}

Solution steps

\frac{d}{d x} (x^{2} + x y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (x y)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (x y) = y + x \frac{d y}{d x}

= 2 x + y + x \frac{d y}{d x}

\frac{d}{d t} (e^{3 c o s (t) + 2 t^{2}})

\frac{\partial}{\partial x} (e^{- 9 x^{2} - 2 y^{2}})

\int sec^{2} (2 x y) d x

\frac{d}{d x} (\frac{x ^{2} - 8 x + 7}{x ^{2} + 9})

\frac{\partial}{\partial x} (t^{2} e^{x} + 3 x^{2})

What is the derivative of x^2+xy ?
The derivative of x^2+xy is 2x+y+x(dy)/(dx)
What is the first derivative of x^2+xy ?
The first derivative of x^2+xy is 2x+y+x(dy)/(dx)