What is the integral of sec^2(2xy) ?

The integral of sec^2(2xy) is 1/(2y)tan(2yx)+C

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integral of sec^2(2xy)

\int sec^{2} (2 x y) d x

\frac{1}{2 y} tan (2 y x) + C

Solution steps

\int sec^{2} (2 x y) d x

Apply u-substitution

: \int \frac{sec ^{2} ( u )}{2 y} d u

= \int \frac{sec ^{2} ( u )}{2 y} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2 y} \cdot \int sec^{2} (u) d u

Use the common integral:

\int sec^{2} (u) d u = tan (u)

= \frac{1}{2 y} tan (u)

Substitute back

u = 2 y x

= \frac{1}{2 y} tan (2 y x)

Add a constant to the solution

= \frac{1}{2 y} tan (2 y x) + C

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What is the integral of sec^2(2xy) ?
The integral of sec^2(2xy) is 1/(2y)tan(2yx)+C