What is the derivative of y=3+log_{2}(x) ?

The derivative of y=3+log_{2}(x) is 1/(ln(2)x)

What is the first derivative of y=3+log_{2}(x) ?

The first derivative of y=3+log_{2}(x) is 1/(ln(2)x)

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derivative of

y = 3 + lo g_{2} (x)

\frac{1}{ln ( 2 ) x}

Solution steps

\frac{d}{d x} (3 + lo g_{2} (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3) + \frac{d}{d x} (lo g_{2} (x))

\frac{d}{d x} (3) = 0

\frac{d}{d x} (lo g_{2} (x)) = \frac{1}{x ln ( 2 )}

= 0 + \frac{1}{x ln ( 2 )}

Simplify

= \frac{1}{ln ( 2 ) x}

d y = x^{2} d x

\frac{d}{d x} (\frac{2 x + 5}{2 x - 5})

\frac{\partial}{\partial x} (26 - x^{2} - y^{2})

\frac{d}{d x} (sec (x^{2} - 1))

(t - 1)^{4}

What is the derivative of y=3+log_{2}(x) ?
The derivative of y=3+log_{2}(x) is 1/(ln(2)x)
What is the first derivative of y=3+log_{2}(x) ?
The first derivative of y=3+log_{2}(x) is 1/(ln(2)x)