What is the d/(dθ)(3+3sin(θ)) ?

The d/(dθ)(3+3sin(θ)) is 3cos(θ)

What is the first d/(dθ)(3+3sin(θ)) ?

The first d/(dθ)(3+3sin(θ)) is 3cos(θ)

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\frac{d}{d θ} (3 + 3 sin (θ))

3 cos (θ)

Solution steps

\frac{d}{d θ} (3 + 3 sin (θ))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (3) + \frac{d}{d θ} (3 sin (θ))

\frac{d}{d θ} (3) = 0

\frac{d}{d θ} (3 sin (θ)) = 3 cos (θ)

= 0 + 3 cos (θ)

Simplify

= 3 cos (θ)

0

t + 2

\int - \frac{26}{x ^{27}} d x

x \to \infty lim (2^{2})

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