What is (\partial)/(\partial x)(ln(7x)) ?

The answer to (\partial)/(\partial x)(ln(7x)) is 1/x

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(\partial)/(\partial x)(ln(7x))

\frac{\partial}{\partial x} (ln (7 x))

\frac{1}{x}

Solution steps

\frac{\partial}{\partial x} (ln (7 x))

Apply the chain rule:

\frac{1}{7 x} \frac{\partial}{\partial x} (7 x)

= \frac{1}{7 x} \frac{\partial}{\partial x} (7 x)

\frac{\partial}{\partial x} (7 x) = 7

= \frac{1}{7 x} \cdot 7

Simplify

\frac{1}{7 x} \cdot 7 : \frac{1}{x}

= \frac{1}{x}

x^{^{''}} + 3 x^{^{'}} = 0, x (0) = 0, x^{^{'}} (0) = - 3

e^{x^{e}}

x \to 6 - lim (x - 6)

y^{^{'}} = 18 x^{2} e^{- y}

f (x) = x^{2} + 3, at x = 2

What is (\partial)/(\partial x)(ln(7x)) ?
The answer to (\partial)/(\partial x)(ln(7x)) is 1/x