What is the (1/(cos^2(x)))^' ?

The (1/(cos^2(x)))^' is 2sec^2(x)tan(x)

What is the first (1/(cos^2(x)))^' ?

The first (1/(cos^2(x)))^' is 2sec^2(x)tan(x)

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(\frac{1}{cos ^{2} ( x )})^{^{'}}

2 sec^{2} (x) tan (x)

Solution steps

(\frac{1}{cos ^{2} ( x )})^{'}

Simplify

\frac{1}{cos ^{2} ( x )} : sec^{2} (x)

= (sec^{2} (x))^{^{'}}

Apply the chain rule:

2 sec (x) (sec (x))^{'}

= 2 sec (x) (sec (x))^{'}

(sec (x))^{'} = sec (x) tan (x)

= 2 sec (x) sec (x) tan (x)

Simplify

2 sec (x) sec (x) tan (x) : 2 sec^{2} (x) tan (x)

= 2 sec^{2} (x) tan (x)

\int 3 sec^{2} (x) d x

x \to 5 lim (2 x^{3} - 3 x + 8)

x^{2} + x, at x = - 4

\int x^{2} 6 x + 8 d x

\int arccos (d) x d x

What is the (1/(cos^2(x)))^' ?
The (1/(cos^2(x)))^' is 2sec^2(x)tan(x)
What is the first (1/(cos^2(x)))^' ?
The first (1/(cos^2(x)))^' is 2sec^2(x)tan(x)