What is the derivative of y=-5/((x+3)^2) ?

The derivative of y=-5/((x+3)^2) is (10)/((x+3)^3)

What is the first derivative of y=-5/((x+3)^2) ?

The first derivative of y=-5/((x+3)^2) is (10)/((x+3)^3)

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derivative of

y = - \frac{5}{( x + 3 ) ^{2}}

\frac{10}{( x + 3 ) ^{3}}

Solution steps

\frac{d}{d x} (- \frac{5}{( x + 3 ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 5 \frac{d}{d x} (\frac{1}{( x + 3 ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 5 \frac{d}{d x} ((x + 3)^{- 2})

Apply the chain rule:

- \frac{2}{( x + 3 ) ^{3}} \frac{d}{d x} (x + 3)

= - \frac{2}{( x + 3 ) ^{3}} \frac{d}{d x} (x + 3)

\frac{d}{d x} (x + 3) = 1

= - 5 (- \frac{2}{( x + 3 ) ^{3}} \cdot 1)

Simplify

- 5 (- \frac{2}{( x + 3 ) ^{3}} \cdot 1) : \frac{10}{( x + 3 ) ^{3}}

= \frac{10}{( x + 3 ) ^{3}}

f (x) = 2 x + 7

\int \frac{( x ^{2} - 1 )}{x ^{3} + x} d x

\frac{d}{d x} (- k e^{l (x - m)} + n e^{- p (x - m)} + q)

\frac{1}{( s - 2 ) ^{2} + 9}

\frac{d}{d j} (6 i + 10 j)

What is the derivative of y=-5/((x+3)^2) ?
The derivative of y=-5/((x+3)^2) is (10)/((x+3)^3)
What is the first derivative of y=-5/((x+3)^2) ?
The first derivative of y=-5/((x+3)^2) is (10)/((x+3)^3)