What is the solution for (2000)/((2000-P)P)P^'=0.05 ?

The solution for (2000)/((2000-P)P)P^'=0.05 is P(t)=-(2000e^{0.05t+c_{1}})/(1-e^{0.05t+c_{1)}}

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(2000)/((2000-P)P)P^'=0.05

\frac{2000}{( 2000 - P ) P} P^{^{'}} = 0.05

P (t) = - \frac{2000 e ^{0.05 t + c_{1}}}{1 - e ^{0.05 t + c_{1}}}

Solution steps

\frac{2000}{( 2000 - P ( t ) ) P ( t )} P^{'} (t) = 0.05

Solve separable ODE:

P (t) = - \frac{2000 e ^{0.05 t + c_{1}}}{1 - e ^{0.05 t + c_{1}}}

P (t) = - \frac{2000 e ^{0.05 t + c_{1}}}{1 - e ^{0.05 t + c_{1}}}

30

y^{^{''}} + y^{^{'}} - 5 x = 0

\int_{- \infty}^{x} \frac{1}{x ^{2}} d x

\frac{10}{s ^{2} + 8 s + 25}

y = 2 + 1 x + 10 x e^{x}, at x = 0

What is the solution for (2000)/((2000-P)P)P^'=0.05 ?
The solution for (2000)/((2000-P)P)P^'=0.05 is P(t)=-(2000e^{0.05t+c_{1}})/(1-e^{0.05t+c_{1)}}