What is the integral from-infinity to x of 1/(x^2) ?

The integral from-infinity to x of 1/(x^2) is -1/x

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integral from-infinity to x of 1/(x^2)

\int_{- \infty}^{x} \frac{1}{x ^{2}} d x

- \frac{1}{x}

Solution steps

\int_{- \infty}^{x} \frac{1}{x ^{2}} d x

Compute the indefinite integral:

\int \frac{1}{x ^{2}} d x = - \frac{1}{x} + C

Compute the boundaries:

\int_{- \infty}^{x} \frac{1}{x ^{2}} d x = - \frac{1}{x} - 0

= - \frac{1}{x} - 0

Simplify

= - \frac{1}{x}

\frac{10}{s ^{2} + 8 s + 25}

y = 2 + 1 x + 10 x e^{x}, at x = 0

y^{^{''}} + y = cos (2 x)

\int (2 - x)^{2} d x

3 y^{^{''}} - 4 y^{^{'}} - 4 y = 0, y (0) = - 7, y^{^{'}} (0) = - 8

What is the integral from-infinity to x of 1/(x^2) ?
The integral from-infinity to x of 1/(x^2) is -1/x