What is the derivative of-0.4x^2+2.2x+4.7 ?

The derivative of-0.4x^2+2.2x+4.7 is -0.8x+2.2

What is the first derivative of-0.4x^2+2.2x+4.7 ?

The first derivative of-0.4x^2+2.2x+4.7 is -0.8x+2.2

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\frac{d}{d x} (- 0.4 x^{2} + 2.2 x + 4.7)

- 0.8 x + 2.2

Solution steps

\frac{d}{d x} (- 0.4 x^{2} + 2.2 x + 4.7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (0.4 x^{2}) + \frac{d}{d x} (2.2 x) + \frac{d}{d x} (4.7)

\frac{d}{d x} (0.4 x^{2}) = 0.8 x

\frac{d}{d x} (2.2 x) = 2.2

\frac{d}{d x} (4.7) = 0

= - 0.8 x + 2.2 + 0

Simplify

= - 0.8 x + 2.2

\frac{d}{d x} (e^{x} (tan (x) - x))

x \to 0 lim (\frac{x}{x + 1})

2 x^{3} + 3 x^{2} - 12 x + 2

\int (x^{2} - 5 x) \cdot e^{x} d x

y = 10 x sin (x), (\frac{π}{2}, 5 π)

What is the derivative of-0.4x^2+2.2x+4.7 ?
The derivative of-0.4x^2+2.2x+4.7 is -0.8x+2.2
What is the first derivative of-0.4x^2+2.2x+4.7 ?
The first derivative of-0.4x^2+2.2x+4.7 is -0.8x+2.2