What is the tangent of y=10xsin(x),(pi/2 ,5pi) ?

The tangent of y=10xsin(x),(pi/2 ,5pi) is y=10x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=10xsin(x),(pi/2 ,5pi)

tangent of

y = 10 x sin (x), (\frac{π}{2}, 5 π)

y = 10 x

Solution steps

Find the slope of

y = 10 x sin (x) : \frac{d y}{d x} = 10 (sin (x) + x cos (x))

Compute the slope of

y = 10 x sin (x)

(\frac{π}{2}, 5 π) : m = 10

Find the line with slope m=

10

and passing through

(\frac{π}{2}, 5 π) : y = 10 x

y = 10 x

\int 3 arctan (x) d x

\frac{d}{d x} (sin (x^{2} + 1))

f (x) = \frac{2}{x}, (4, \frac{1}{2})

\frac{d}{d x} (1 + 2 cos (x))

\frac{d}{d x} (e^{x^{2} - 4} + 3 x + 5)

What is the tangent of y=10xsin(x),(pi/2 ,5pi) ?
The tangent of y=10xsin(x),(pi/2 ,5pi) is y=10x