What is the derivative of 1+2cos(x) ?

The derivative of 1+2cos(x) is -2sin(x)

What is the first derivative of 1+2cos(x) ?

The first derivative of 1+2cos(x) is -2sin(x)

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\frac{d}{d x} (1 + 2 cos (x))

- 2 sin (x)

Solution steps

\frac{d}{d x} (1 + 2 cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (2 cos (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (2 cos (x)) = - 2 sin (x)

= 0 - 2 sin (x)

Simplify

= - 2 sin (x)

\frac{d}{d x} (e^{x^{2} - 4} + 3 x + 5)

(- 4, 4), (3, - 4)

(y^{2} + y x) d x + (x^{2}) d y = 0

y = (x - 2)^{4}

\frac{d}{d x} (cos ((2 x^{2} + 1)^{7}))

What is the derivative of 1+2cos(x) ?
The derivative of 1+2cos(x) is -2sin(x)
What is the first derivative of 1+2cos(x) ?
The first derivative of 1+2cos(x) is -2sin(x)