What is the slope of (x+2)^2+(y-3)^2=37,(4,2) ?

The slope of (x+2)^2+(y-3)^2=37,(4,2) is 6

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slope of (x+2)^2+(y-3)^2=37,(4,2)

slope

(x + 2)^{2} + (y - 3)^{2} = 37, (4, 2)

6

Solution steps

(x + 2)^{2} + (y - 3)^{2} = 37

Use implicit differentiation to find the slope of

(x + 2)^{2} + (y - 3)^{2} = 37

Implicit Derivative

\frac{d y}{d x}

(x + 2)^{2} + (y - 3)^{2} = 37 : - \frac{x + 2}{y - 3}

- \frac{x + 2}{y - 3}

Find the slope at

(4, 2) : 6

6

y^{^{'}} = r - k y

x \to - 1 lim (x ∣ x + 1 ∣)

f (x) = 7 y^{7} - 4 y^{6} + 35 y^{4} - 24 y^{2}

x \to 0 lim (\frac{( ( x ^{2} + 3 ) )}{x})

f (x) = (8 - 9 x) (8 + 9 x), at x = 9

What is the slope of (x+2)^2+(y-3)^2=37,(4,2) ?
The slope of (x+2)^2+(y-3)^2=37,(4,2) is 6