What is the limit as x approaches 3 of sqrt(x^2+16) ?

The limit as x approaches 3 of sqrt(x^2+16) is 5

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limit as x approaches 3 of sqrt(x^2+16)

x \to 3 lim (x^{2} + 16)

5

Solution steps

x \to 3 lim (x^{2} + 16)

Plug in the value

x = 3

= 3^{2} + 16

Simplify

3^{2} + 16 : 5

= 5

\frac{\partial}{\partial x} (25 - 5 x^{2} - y^{2})

x \to \infty lim (2 x + 5)

\int_{0}^{π} 3 sin^{2} (t co) s^{4} t d t

f (x) = \frac{3 x ^{2} e ^{x} - 4}{x ^{2}}

x \to 1 - lim (2 x^{4} - 9 x^{3} + 7)

What is the limit as x approaches 3 of sqrt(x^2+16) ?
The limit as x approaches 3 of sqrt(x^2+16) is 5