What is the derivative of 10(4e^{x^2}x^3+6e^{x^2}x) ?

The derivative of 10(4e^{x^2}x^3+6e^{x^2}x) is 10(8e^{x^2}x^4+24e^{x^2}x^2+6e^{x^2})

What is the first derivative of 10(4e^{x^2}x^3+6e^{x^2}x) ?

The first derivative of 10(4e^{x^2}x^3+6e^{x^2}x) is 10(8e^{x^2}x^4+24e^{x^2}x^2+6e^{x^2})

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derivative of

10 (4 e^{x^{2}} x^{3} + 6 e^{x^{2}} x)

10 (8 e^{x^{2}} x^{4} + 24 e^{x^{2}} x^{2} + 6 e^{x^{2}})

Solution steps

\frac{d}{d x} (10 (4 e^{x^{2}} x^{3} + 6 e^{x^{2}} x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 10 \frac{d}{d x} (4 e^{x^{2}} x^{3} + 6 e^{x^{2}} x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= 10 (\frac{d}{d x} (4 e^{x^{2}} x^{3}) + \frac{d}{d x} (6 e^{x^{2}} x))

\frac{d}{d x} (4 e^{x^{2}} x^{3}) = 4 (2 e^{x^{2}} x^{4} + 3 e^{x^{2}} x^{2})

\frac{d}{d x} (6 e^{x^{2}} x) = 6 (2 e^{x^{2}} x^{2} + e^{x^{2}})

= 10 (4 (2 e^{x^{2}} x^{4} + 3 e^{x^{2}} x^{2}) + 6 (2 e^{x^{2}} x^{2} + e^{x^{2}}))

Expand

4 (2 e^{x^{2}} x^{4} + 3 e^{x^{2}} x^{2}) + 6 (2 e^{x^{2}} x^{2} + e^{x^{2}}) : 8 e^{x^{2}} x^{4} + 24 e^{x^{2}} x^{2} + 6 e^{x^{2}}

= 10 (8 e^{x^{2}} x^{4} + 24 e^{x^{2}} x^{2} + 6 e^{x^{2}})

x \to 0 lim (lo g_{10} (x))

\int \frac{1}{x ^{2} x ^{2} + 16} d x

y^{^{''}} - 2 y + 1 = 0

x^{2} - 11 y^{2}, y a s

(3 - 5 x)^{9}

What is the derivative of 10(4e^{x^2}x^3+6e^{x^2}x) ?
The derivative of 10(4e^{x^2}x^3+6e^{x^2}x) is 10(8e^{x^2}x^4+24e^{x^2}x^2+6e^{x^2})
What is the first derivative of 10(4e^{x^2}x^3+6e^{x^2}x) ?
The first derivative of 10(4e^{x^2}x^3+6e^{x^2}x) is 10(8e^{x^2}x^4+24e^{x^2}x^2+6e^{x^2})