What is the solution for y^{''}-2y+1=0 ?

The solution for y^{''}-2y+1=0 is y=c_{1}e^{sqrt(2)t}+c_{2}e^{-sqrt(2)t}+1/2

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y^{''}-2y+1=0

y^{^{''}} - 2 y + 1 = 0

y = c_{1} e^{2 t} + c_{2} e^{- 2 t} + \frac{1}{2}

Solution steps

y^{''} (t) - 2 y + 1 = 0

Solve linear ODE:

y = c_{1} e^{2 t} + c_{2} e^{- 2 t} + \frac{1}{2}

y = c_{1} e^{2 t} + c_{2} e^{- 2 t} + \frac{1}{2}

x^{2} - 11 y^{2}, y a s

(3 - 5 x)^{9}

\int e^{\frac{3 x}{2}} d x

n = 1 \sum \infty \frac{n + 2}{3 n + 4}

What is the solution for y^{''}-2y+1=0 ?
The solution for y^{''}-2y+1=0 is y=c_{1}e^{sqrt(2)t}+c_{2}e^{-sqrt(2)t}+1/2