What is the sum from n=1 to infinity of (n+2)/(3n+4) ?

The sum from n=1 to infinity of (n+2)/(3n+4) is diverges

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sum from n=1 to infinity of (n+2)/(3n+4)

n = 1 \sum \infty \frac{n + 2}{3 n + 4}

diverges

Solution steps

n = 1 \sum \infty \frac{n + 2}{3 n + 4}

Apply Series Divergence Test:

diverges

= diverges

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What is the sum from n=1 to infinity of (n+2)/(3n+4) ?
The sum from n=1 to infinity of (n+2)/(3n+4) is diverges